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electromagnetism - Why is $K_{\alpha,3/2}$ always more intense than $K_{\ alpha,1/2}$ in copper? - Physics Stack Exchange
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The K-beta/K-alpha intensity ratios of some elements at different azimuthal scattering angles at 59.54 keV
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Experimental setup of Cu-K-alpha source with two variants dedicated to:... | Download Scientific Diagram
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If `lambda_(Cu)` is the wavelength of `K_(alpha)` X-ray line of copper (atomic number `29`) - YouTube
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